540. Single Element in a Sorted Array
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这道题从中间开始找，然后看左边长度是偶数，还是奇数，往是长度是奇数的那边找
public class Solution { public int singleNonDuplicate(int[] nums) { int mid = nums.length/2; return findSingle(nums,0,nums.length-1); } private int findSingle(int[] nums, int start, int end) { int mid = (end-start)/2+start; if (mid == nums.length-1)return nums[nums.length-1]; if (mid == 0)return nums[0]; if (nums[mid-1] == nums[mid]){ if((mid-1)%2==1){ return findSingle(nums,start,mid-1); }else{ return findSingle(nums,mid+1,end); } }else if (nums[mid+1]==nums[mid]){ if((mid+1)%2==1){ return findSingle(nums,mid+1,end); }else{ return findSingle(nums,start,mid-1); } }else return nums[mid]; }}阅读全文
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