基于51单片机开发板的应用（数码管）

来源：互联网发布：vslam 算法公司编辑：程序博客网时间：2024/05/18 00:08

在对LED灯的应用有了一定的了解之后，我开始学习了一些关于数码管的应用。

在我的开发板上，有独立共阳管和八位共阴管。数码管从高位到低位的段码依次是h(dp),g,f,e,d,c,b,a共八位。共阴管是“1”表示亮，“0”表示灭，而共阳管则是相反的。顺便提一句，若是要检测数码管是否完好，可以用数码管“8”来检测。

若是要在数码管上显示0~F，则可以用一套固定的十六进制数表示，可以放在数组中，为{0x3f,0x06,0x5b,0x4f,0x66,0x6d,0x7d,0x07,0x7f,0x6f,0x77,0x7c,0x39,0x5e,0x79,0x71}。这一个数组是用来表示共阴管的亮的，而若是共阳管的时候，需要在前面加上“~”。

独立共阳管显示0-F

//显示0-F#include<reg51.h>unsigned char code LED[]={0x3f,0x06,0x5b,0x4f,0x66,0x6d,0x7d,0x07,0x7f,0x6f,0x77,0x7c,0x39,0x5e,0x79,0x71};void DelayUs2x(unsigned char t){while(--t);}void DelayMs(unsigned char t){while(t--){DelayUs2x(245);DelayUs2x(245);}}void main(void){unsigned char i;while(1){for(i=0; i<16; i++){P1=~LED[i]; //取反DelayMs(200);        //大约延迟200ms}}}

8位共阴管显示有静态扫描和动态扫描两种方式。

1、8个同时显示0-F 静态扫描

#include<reg51.h>#define DataPort P0  //数据端口sbit Seg_latch=P2^2;  //段锁存sbit Bit_latch=P2^3;      //位锁存   两者必须是取反，只能有一个成立unsigned char code Seg_code[]={0x3f,0x06,0x5b,0x4f,0x66,0x6d,0x7d,0x07,0x7f,0x6f,0x77,0x7c,0x39,0x5e,0x79,0x71};void DelayUs2x(unsigned char t){while(--t);}void DelayMs(unsigned char t){while(t--){DelayUs2x(245);DelayUs2x(245);}}void main(void){unsigned char i;while(1){for(i=0; i<16; i++){DataPort=Seg_code[i];             //控制段锁存，显示0-FSeg_latch=1;                      //开段锁存  Seg_latch=0;                      //关段锁存值进来了DataPort=0x00;  //控制位锁存（低电平有效），8个管同时亮Bit_latch=1;  //开位锁存Bit_latch=0;  //关位锁存DelayMs(200);}}}

2、显示0-F：先是显示0-7，然后显示8-F 位：第1-8位，第1-8位动态扫描

#include<reg51.h>#define DataPort P0sbit Seg_latch=P2^2;sbit Bit_latch=P2^3;unsigned char code Seg_code[]={0x3f,0x06,0x5b,0x4f,0x66,0x6d,0x7d,0x07,0x7f,0x6f,0x77,0x7c,0x39,0x5e,0x79,0x71};unsigned char code Bit_code[]={0xfe,0xfd,0xfb,0xf7,0xef,0xdf,0xbf,0x7f,0xfe,0xfd,0xfb,0xf7,0xef,0xdf,0xbf,0x7f};void delay(unsigned char i){while(i--)   ;}void main(void){unsigned char i;while(1){for(i=0; i<16; i++){DataPort=0x00;//消除重影Seg_latch=1;Seg_latch=0;DataPort=Bit_code[i]; //位码Bit_latch=1;Bit_latch=0;DataPort=Seg_code[i]; //段码Seg_latch=1;Seg_latch=0;delay(100000);} }}

阅读全文

0 0