hdu2817 A sequence of numbers
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题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=2817
题意:给你一个数列的前三项,让你求第k项,这个数列可能是等差也可能是等比
解析:直接判断等差还是等比,等比用快速幂,等差就直接套公式a0+(n-1)*d
#include <bits/stdc++.h>using namespace std;const int mod = 200907;long long qpow(long long x,int n){ long long res = 1; while(n) { if(n&1) res = res*x%mod; x = x*x%mod; n>>=1; } return res;}int main(void){ int n; scanf("%d",&n); while(n--) { long long t1,t2,t3,k; scanf("%I64d %I64d %I64d %I64d",&t1,&t2,&t3,&k); long long ans; if(t2-t1==t3-t2) { long long d = t2-t1; ans = (t1+(k-1)*d%mod)%mod; } else { long long q = t3/t2; ans = t1*qpow(q,k-1)%mod; } printf("%I64d\n",ans); } return 0;}
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