计算机图形学——绘制钻石图案

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要求：绘制钻石图案。将一圆周进行n等分，然后将所有的等分用直线连接，构成图案。

n=8

q =2*p/n

X=2*r*cos(q)

Y=r*sin(q)

#include <GL/glut.h>#include <math.h>#include <stdlib.h>#include <stdio.h>#define pi 3.14159265int n=8;int R=200,CX=250,CY=250;int *point;void initGraph(void);void drawCircle(int cx, int cy, int r);void display(void);void drawLine(int x1, int y1, int x2, int y2);void main(int argc, char **argv){     float w,wi;     glutInit(&argc,argv);     glutInitDisplayMode(GLUT_SINGLE|GLUT_RGB) ;     glutInitWindowSize(500,500);     glutCreateWindow("n阶钻石图案");     initGraph();point=(int*)malloc(sizeof(int)*n*2);//申请存储空间w=2*pi/n;wi=w/2;for(int i=0;i<2*n;i+=2){point[i]=(int)(CX+R*cos(wi));point[i+1]=(int)(CY+R*sin(wi));wi+=w;}    glutDisplayFunc(display);    glutMainLoop();    if(point!=NULL)free(point);//释放存储空间}void initGraph (void){    glClearColor(0.0,0.0,0.0,0.0);    gluOrtho2D(0.0,500.0,0.0,500.0);//窗口坐标左下角(0,0), 右上角(500,500)}void display(void){     glClear(GL_COLOR_BUFFER_BIT) ;     glColor3f(5.0, 3.0, 4.0) ;     for(int i=0;i<2*n-2;i+=2){          for(int j=i+2;j<2*n;j+=2){              drawLine(point[i],point[i+1],point[j],point[j+1]);           }    }} void drawLine(int x1, int y1, int x2, int y2) {    glBegin(GL_LINES);    glVertex2d(x1, y1);    glVertex2d(x2, y2);    glEnd();    glFlush() ;}

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