[leetcode]Jump Game II

45. Jump Game II

Given an array of non-negative integers, you are initially positioned at the first index of the array.Each element in the array represents your maximum jump length at that position.Your goal is to reach the last index in the minimum number of jumps.For example:Given array A = [2,3,1,1,4]The minimum number of jumps to reach the last index is 2. (Jump 1 step from index 0 to 1, then 3 steps to the last index.)

这是我的解法，思路类似于这个discuss，将此问题看做bfs.

int jump(vector<int>& nums){    int N = nums.size();    if (N <= 1) return 0;    // right is the right bound for this level    // cover is the right bound for next level    int right = 0 + nums[0], step = 1, cover = right;    for (int i = 1; i <= right; ++i)    {        if (right >= N - 1) return step;        cover = max(nums[i] + i, cover);        if (i == right)        {            right = cover;            ++step;        }    }    return 0;}