Valid Square
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Given the coordinates of four points in 2D space, return whether the four points could construct a square.
根据四个二维坐标,判断这四个点能否构成一个正方形。
思路1:
根据正方形的特点,任意两点之间的距离只有两种, 一是边,二是对角线;根据这个特性,计算任意两点之间距离。
public class Solution { public boolean validSquare(int[] p1, int[] p2, int[] p3, int[] p4) { HashSet set = new HashSet(); int d1 = distance(p1, p2); int d2 = distance(p1, p3); int d3 = distance(p1, p4); int d4 = distance(p2, p3); int d5 = distance(p2, p4); int d6 = distance(p3, p4); if (d1 == 0 || d2 == 0 || d3 == 0 || d4 == 0 || d5 == 0 || d6 == 0) return false; set.add(d1); set.add(d2); set.add(d3); set.add(d4); set.add(d5); set.add(d6); if (set.size() == 2) return true; return false; } private int distance(int[] x, int[] y) { return (int) (Math.pow(x[0] - y[0], 2) + Math.pow(x[1] - y[1], 2)); } }
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