request.getRequestURI()的使用
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request.getRequestURI() /jqueryWeb/resources/request.jsp
request.getRequestURL() http://localhost:8080/jqueryWeb/resources/request.jsp
request.getContextPath()/jqueryWeb
request.getServletPath()/resources/request.jsp
注: resources为WebContext下的目录名
jqueryWeb 为工程名
<%=request.getRequestURI() %>
<%=request.getRequestURL() %>
<%=request.getContextPath()%>
<%=request.getServletPath() %>
<%=request.getPathInfo() %>
结果:
/test-struts.jsp
http://127.0.0.1:8080/test-struts.jsp
/test-struts.jsp
null
配置:
/test-struts.jsp
假定你的web application 名称为news,你在浏览器中输入请求路径:
http://localhost:8080/news/main/list.jsp
则执行下面向行代码后打印出如下结果:
1、 System.out.println(request.getContextPath());
打印结果:/news
2、System.out.println(request.getServletPath());
打印结果:/main/list.JSP
3、 System.out.println(request.getRequestURI());
打印结果:/news/main/list.JSp
4、 System.out.println(request.getRealPath(“/”));
打印结果:F:\tomcat 6.0\webapps\news\test
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