iOS 根据时间排序

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这个是回答这篇文章的问题
http://blog.csdn.net/sinat_30162391/article/details/50916219#comments

创建个date模型

#import <Foundation/Foundation.h>@interface Date : NSObject@property (nonatomic, copy) NSString *time;@end

之后赋值进行排序

    Date *d1 = [[Date alloc] init];    d1.time = @"2012-12-02";    Date *d2 = [[Date alloc] init];    d2.time = @"2412-12-02";    Date *d3 = [[Date alloc] init];    d3.time = @"2312-12-02";    Date *d4 = [[Date alloc] init];    d4.time = @"2312-12-02";    Date *d5 = [[Date alloc] init];    d5.time = @"2812-08-02";    Date *d6 = [[Date alloc] init];    d6.time = @"0000-09-02";    _dataArray = [NSMutableArray array];    [_dataArray addObject:d1];    [_dataArray addObject:d2];    [_dataArray addObject:d3];    [_dataArray addObject:d4];    [_dataArray addObject:d5];    [_dataArray addObject:d6];    for (int i = 0; i < _dataArray.count; i ++) {        Date *d = [[Date alloc] init];        d = _dataArray[i];        NSLog(@"排序前 == %@", d.time);    }    NSLog(@"\n");    NSSortDescriptor *sorter = [[NSSortDescriptor alloc] initWithKey:@"time" ascending:YES];    NSMutableArray *sortDescriptors = [[NSMutableArray alloc] initWithObjects:&sorter count:1];    NSArray *sortArray = [_dataArray sortedArrayUsingDescriptors:sortDescriptors];    for (int j = 0; j < sortArray.count; j ++) {        Date *d = [[Date alloc] init];        d = sortArray[j];        NSLog(@"排序后 == %@", d.time);    }

2017-06-10 19:59:35.046 TimeSort[4740:678220] 排序前 == 2012-12-022017-06-10 19:59:35.047 TimeSort[4740:678220] 排序前 == 2412-12-022017-06-10 19:59:35.047 TimeSort[4740:678220] 排序前 == 2312-12-022017-06-10 19:59:35.047 TimeSort[4740:678220] 排序前 == 2312-12-022017-06-10 19:59:35.047 TimeSort[4740:678220] 排序前 == 2812-08-022017-06-10 19:59:35.047 TimeSort[4740:678220] 排序前 == 0000-09-022017-06-10 19:59:35.048 TimeSort[4740:678220] 2017-06-10 19:59:35.048 TimeSort[4740:678220] 排序后 == 0000-09-022017-06-10 19:59:35.048 TimeSort[4740:678220] 排序后 == 2012-12-022017-06-10 19:59:35.048 TimeSort[4740:678220] 排序后 == 2312-12-022017-06-10 19:59:35.048 TimeSort[4740:678220] 排序后 == 2312-12-022017-06-10 19:59:35.048 TimeSort[4740:678220] 排序后 == 2412-12-022017-06-10 19:59:35.049 TimeSort[4740:678220] 排序后 == 2812-08-02

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