Financial Management

Financial Management

时间限制：3000 ms  |  内存限制：65535 KB

难度：1

描述

Larry graduated this year and finally has a job. He's making a lot of money, but somehow never seems to have enough. Larry has decided that he needs to grab hold of his financial portfolio and solve his financing problems. The first step is to figure out what's been going on with his money. Larry has his bank account statements and wants to see how much money he has. Help Larry by writing a program to take his closing balance from each of the past twelve months and calculate his average account balance.

输入

The input will be twelve lines. Each line will contain the closing balance of his bank account for a particular month. Each number will be positive and displayed to the penny. No dollar sign will be included. 

输出

The output will be a single number, the average (mean) of the closing balances for the twelve months. It will be rounded to the nearest penny, preceded immediately by a dollar sign, and followed by the end-of-line. There will be no other spaces or characters in the output. 

样例输入

100.00489.1212454.121234.10823.05109.205.271542.25839.1883.991295.011.75

样例输出

1581.42

AC代码：

#include<iostream>
#include<iomanip>
using namespace std;
int main()
{
double data,sum=0;
for(int i=0;i<12;i++)
{
cin>>data;
sum+=data;

}
cout<<fixed<<setprecision(2)<<sum/12;
return 0;
}

注：1、setprecision(n) 默认设置输出的数字的总位数为n，包含整数和小数部分；

     2、setiosflags(ios::fixed) 默认输出6位，必须与setprecision(n)配合使用，用来控制小数的位数，不够补0；

     3、使用setprecision(n)可控制输出流显示浮点数的数字个数。C++默认的流输出数值有效位是6。
  


setiosflags(ios::fixed)是用定点方式表示实数