A. An abandoned sentiment from past
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解题说明:此题只需要判断具有一种不是单调递增的序列即可。
#include<cstdio>#include<algorithm>#include<cstring>#include<cstdlib>#include<iostream>using namespace std;int main(){ int n,k,i,j,a[101],b[101],t; int ok=0,l=0; while(scanf("%d%d",&n,&k)!=EOF) {memset(a,0,sizeof(a));for(i=0;i<n;i++){scanf("%d",&a[i]);}for(i=0;i<k;i++){scanf("%d",&b[i]);}if(k>=2){ok=1;}for(i=0;i<n;i++){ if(a[i]==0) {a[i]=b[l++]; }}for(i=0;i<n-1;i++){ if(a[i]>=a[i+1]) { ok=1; }}if(ok==1){printf("Yes\n");}else{printf("No\n");} }return 0;}
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