记负均正

#include<bits/stdc++.h>using namespace std;int main()    {    int n;    while(cin>>n)        {        int sum=0;        int cnt1=0;        int cnt2=0;        int x;        for(int i=0;i<n;i++)            {            cin>>x;            if(x<0)cnt1++;            if(x>0)sum+=x,cnt2++;        }        cout<<cnt1<<" ";        if(sum%cnt2==0)cout<<sum/cnt2<<endl;        else {            double ans=sum*1.0/cnt2;            printf("%.1f\n",ans);        }            }    return 0;}