LeetCode-599. Minimum Index Sum of Two Lists

Suppose Andy and Doris want to choose a restaurant for dinner, and they both have a list of favorite restaurants represented by strings.

You need to help them find out their common interest with the least list index sum. If there is a choice tie between answers, output all of them with no order requirement. You could assume there always exists an answer.

Example 1:

Input:["Shogun", "Tapioca Express", "Burger King", "KFC"]["Piatti", "The Grill at Torrey Pines", "Hungry Hunter Steakhouse", "Shogun"]Output: ["Shogun"]Explanation: The only restaurant they both like is "Shogun".

Example 2:

Input:["Shogun", "Tapioca Express", "Burger King", "KFC"]["KFC", "Shogun", "Burger King"]Output: ["Shogun"]Explanation: The restaurant they both like and have the least index sum is "Shogun" with index sum 1 (0+1).

Note:

1. The length of both lists will be in the range of [1, 1000].
2. The length of strings in both lists will be in the range of [1, 30].
3. The index is starting from 0 to the list length minus 1.
4. No duplicates in both lists.  

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这道题属于数组找相同字符串，可以利用集合来进行操作实现。

public class Solution {    public String[] findRestaurant(String[] list1, String[] list2) {        Map<String,Integer> map = new HashMap();List<String> list = new ArrayList<>();int minIndex =2000;for(int i=0;i<list1.length;i++){map.put(list1[i],i);}for(int j=0;j<list2.length;j++){if(map.containsKey(list2[j])){int indexOfMap = map.get(list2[j]);if(indexOfMap+j == minIndex){list.add(list2[j]);}else if(indexOfMap+j < minIndex){list.clear();list.add(list2[j]);minIndex = indexOfMap+j;}}}String [] result = new String[list.size()];        for(int k =0;k<list.size();k++){        result[k] = list.get(k);        }        return result;    }}