iOS开发中获取字符串中的URL

来源：互联网发布：ubuntu服务器版安装编辑：程序博客网时间：2024/06/06 13:07

用webview在程序中加载URL内容的时候，首先需要获取URL，但是有些URL却隐藏在字符串中，这时我们就要解析字符串使用正则表达式从中取出URL。代码如下：

NSString *str = @"我是链接http://www.baidu.com";NSString *URL;NSSArray urlArr;if([self isUrl:str]) {    URL = str;} else {    urlArr = [self getURLFromStr:str];    URL = urlArr[0];}

检查字符串是否是URL

- (BOOL)isURL:(NSString *)url {    if(url.length < 1)        return NO;    if (url.length>4 && [[url substringToIndex:4] isEqualToString:@"www."]) {        url = [NSString stringWithFormat:@"http://%@",url];    } else {        url = url;    }    NSString *urlRegex = @"(https|http|ftp|rtsp|igmp|file|rtspt|rtspu)://((((25[0-5]|2[0-4]\\d|1?\\d?\\d)\\.){3}(25[0-5]|2[0-4]\\d|1?\\d?\\d))|([0-9a-z_!~*'()-]*\\.?))([0-9a-z][0-9a-z-]{0,61})?[0-9a-z]\\.([a-z]{2,6})(:[0-9]{1,4})?([a-zA-Z/?_=]*)\\.\\w{1,5}";NSPredicate* urlTest = [NSPredicate predicateWithFormat:@"SELF MATCHES %@", urlRegex];    return [urlTest evaluateWithObject:url];}

从字符串中获取URL

- (NSArray*)getURLFromStr:(NSString *)string {    NSError *error;    //可以识别url的正则表达式    NSString *regulaStr = @"((http[s]{0,1}|ftp)://[a-zA-Z0-9\\.\\-]+\\.([a-zA-Z]{2,4})(:\\d+)?(/[a-zA-Z0-9\\.\\-~!@#$%^&*+?:_/=<>]*)?)|(www.[a-zA-Z0-9\\.\\-]+\\.([a-zA-Z]{2,4})(:\\d+)?(/[a-zA-Z0-9\\.\\-~!@#$%^&*+?:_/=<>]*)?)";    NSRegularExpression *regex = [NSRegularExpression regularExpressionWithPattern:regulaStr    options:NSRegularExpressionCaseInsensitive    error:&error];    NSArray *arrayOfAllMatches = [regex matchesInString:string    options:0    range:NSMakeRange(0, [string length])];    //NSString *subStr;    NSMutableArray *arr=[[NSMutableArray alloc] init];    for (NSTextCheckingResult *match in arrayOfAllMatches){        NSString* substringForMatch;        substringForMatch = [string substringWithRange:match.range];        [arr addObject:substringForMatch];    }    return arr;}

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