矩阵乘法编写,从文件输入输出

题目

matrixA.txt , shape(1,50)
matrixB.txt , shape(50,10)
1. 讀取matrixA.txt,matrixB.txt中的矩陣
2. 進行矩陣乘法 - matrixA * matrixB
3. 將得到的矩陣數值，由小到大排序後輸出至ans_one.txt,每个数字要换行

文件样式

• matrixA.txt
  
  -matrixB.txt
  

直接上代码

#include <iostream>#include <fstream>#include <vector>#include <string>#include <algorithm>using namespace std;//忽视硬编码//1*50ifstream matrixFile1("/home/wuxiao/MyGithub/ML/homework1/2017ML_HW0_data/matrixA.txt");//50*10ifstream matrixFile2("/home/wuxiao/MyGithub/ML/homework1/2017ML_HW0_data/matrixB.txt");ofstream outputFile("/home/wuxiao/MyGithub/ML/homework1/2017ML_HW0_data/Q1_ans.txt");vector<int> matrixANum;vector<int> matrixBNum;vector<int> outputFileNum;void splitString(const string& s, vector<int>& v, const string& c){    string::size_type pos1, pos2;    pos2 = s.find(c);    pos1 = 0;    while(string::npos != pos2)    {        v.push_back(strtoll(s.substr(pos1, pos2-pos1).c_str(),NULL,10));        pos1 = pos2 + c.size();        pos2 = s.find(c, pos1);    }    if(pos1 != s.length())    {        v.push_back(strtoll(s.substr(pos1).c_str(),NULL,10));    }}void getFileNumToArray(ifstream &file,int row,vector<int> &output){    string tempString = "";    for(int i=0;i<row;i++)    {        getline(file,tempString);        splitString(tempString,output,",");    }}void getOutputNum(vector<int> &file1,vector<int> &file2,int times,vector<int> &outputFile){    for(int i=0;i<times;i++)    {        int sum = 0;        for(size_t j=0;j<file1.size();j++)        {            sum += file1[j] * file2[file1.size() * i + j];        }        outputFile.push_back(sum);    }    sort(outputFile.begin(),outputFile.end());}int main() {    if(!matrixFile1 || !matrixFile2 || !outputFile)    {        cout<<"unable to open inputFile or outputFile!"<<endl;        return -1;    }    //读取输入文件的value到数组    getFileNumToArray(matrixFile1,1,matrixANum);    getFileNumToArray(matrixFile2,50,matrixBNum);    //计算矩阵乘积结果    getOutputNum(matrixANum,matrixBNum,10,outputFileNum);    //输出写入文件    vector<int>::iterator iter = outputFileNum.begin();    for(iter = outputFileNum.begin();iter != outputFileNum.end();iter++)    {        outputFile<<*iter<<'\n';    }    return 0;}