atoX 与 strtoX

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在很多时候我们都很清楚 atoX 系列函数: atoi , atol , atof
新来的一系列函数:  strtol,  strtoul, strtod 
通常有如下的关系:
1. 对应关系其中: 

          atoi   (把字符串转到整形)    --对应--   strtol  (把字符串转到长整形)           

          atol   (把字符串转到长整形)    --对应--   strtol  (把字符串转到长整形)           

          atof   (把字符串转到浮点数)    --对应--   strtod (把字符串转到浮点数) 
2. atoX 系列是 三十年前的函数 strtoX 系列是后十年产品


3. atoX 系列接口,没有成功失败的区别(标准实现中),    strtoX 系列接口,有成功失败的区别


    比如:int i_atoi_lfs =  atoi(""); 与 int i_atoi_rfs = atoi("0"); 两个得到的是一样的,没有任何区别         

     而: int i_atoi_lfs =  strtol  ("", NULL,10); 与 int i_atoi_rfs = strtol  ("0", NULL,10);  得到的结果都是0,但是左边会置失败标志位。


4. msvcr80.dll  的具体实现:

 

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int __cdecl atoi(__in_zconst char *_Str){  return_tstoi(_Str);  }   
int __cdecl _tstoi(     const _TCHAR *nptr        ){    return (int)_tstol(nptr);}
int __cdecl _tstoi(     const _TCHAR *nptr        ){    return (int)_tstol(nptr);}
long __cdecl _tstol(const _TCHAR *nptr){return _tcstol(nptr, NULL, 10);}
#define _tcstol   strtol
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<pre class="brush:cpp">extern"C" long __cdecl strtol (
        constchar *nptr,
        char**endptr,
        intibase
        )
{
    if(__locale_changed == 0)
    {
        return(long) strtoxl(&__initiallocalestructinfo, nptr, (constchar **)endptr, ibase, 0);
    }
    else
    {
        return(long) strtoxl(NULL, nptr, (constchar **)endptr, ibase, 0);
    }
}
</pre>
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staticunsigned long__cdecl strtoxl (
        _locale_t plocinfo,
        constchar *nptr,
        constchar **endptr,
        intibase,
        intflags
        )
{
        constchar *p;
        charc;
        unsignedlong number;
        unsigned digval;
        unsignedlong maxval;
        _LocaleUpdate _loc_update(plocinfo);
 
        /* validation section */
        if(endptr != NULL)
        {
            /* store beginning of string in endptr */
            *endptr = (char*)nptr;
        }
        _VALIDATE_RETURN(nptr != NULL, EINVAL, 0L);
        _VALIDATE_RETURN(ibase == 0 || (2 <= ibase && ibase <= 36), EINVAL, 0L);
 
        p = nptr;                      /* p is our scanning pointer */
        number = 0;                    /* start with zero */
//1. 这里关注到,函数没有检查传入的原字符指针是否为空, 如果传递了一个空的就崩了....
        c = *p++;                      /* read char */
        while( _isspace_l((int)(unsignedchar)c, _loc_update.GetLocaleT()) )
            c = *p++;              /* skip whitespace */
 
//2. 不要期望能够 转换负负得正的字符串, 注意 "--100" 得到 0 ,  "-100" 得到 -100
        if(c == '-') {
            flags |= FL_NEG;       /* remember minus sign */
            c = *p++;
        }
        elseif (c == '+')
            c = *p++;              /* skip sign */
//3.  基数是 2 到 36 的闭区间 , [2, 36]
        if(ibase < 0 || ibase == 1 || ibase > 36) {
            /* bad base! */
            if(endptr)
                /* store beginning of string in endptr */
                *endptr = nptr;
            return0L;              /* return 0 */
        }
 
//4. 如果转换的时候基数输入是0, 则基数取决于原字符的前面两个字符,
// 以非0开头的是 10进制字符串,
// 以0x或者0X开头的是 16进制字符串,
// 而仅仅以 0开头的是 8进制
        elseif (ibase == 0) {
            /* determine base free-lance, based on first two chars of
               string */
            if(c != '0')
                ibase = 10;
            elseif (*p == 'x'|| *p == 'X')
                ibase = 16;
            else
                ibase = 8;
        }
 
//  {{{   源码里面,这个地方 有这么一段 暂时不知道是干嘛的, 在我看来貌似是多余的
        if(ibase == 0) {
            /* determine base free-lance, based on first two chars of
               string */
            if(c != '0')
                ibase = 10;
            elseif (*p == 'x'|| *p == 'X')
                ibase = 16;
            else
                ibase = 8;
        }
//}}}
 
// 5. 如果是 16 进制,则跳过0x 或者 0X 的前缀
        if(ibase == 16) {
            /* we might have 0x in front of number; remove if there */
            if(c == '0' && (*p == 'x' || *p =='X')) {
                ++p;
                c = *p++;      /* advance past prefix */
            }
        }
 
// 6. 下面就是读取字符串,然后按照 local 解析应用的数值, 如果在转换过程中出现各种情况都会对标志位flags 进行标记
        /* if our number exceeds this, we will overflow on multiply */
        maxval = ULONG_MAX / ibase;
 
 
        for(;;) {      /* exit in middle of loop */
            /* convert c to value */
            if( __ascii_isdigit_l((int)(unsignedchar)c, _loc_update.GetLocaleT()) )
                digval = c -'0';
            elseif ( __ascii_isalpha_l((int)(unsignedchar)c, _loc_update.GetLocaleT()) )
                digval = __ascii_toupper(c) -'A' + 10;
            else
                break;
            if(digval >= (unsigned)ibase)
                break;         /* exit loop if bad digit found */
 
            /* record the fact we have read one digit */
            flags |= FL_READDIGIT;
 
            /* we now need to compute number = number * base + digval,
               but we need to know if overflow occured.  This requires
               a tricky pre-check. */
 
            if(number < maxval || (number == maxval &&
                        (unsignedlong)digval <= ULONG_MAX % ibase)) {
                /* we won't overflow, go ahead and multiply */
                number = number * ibase + digval;
            }
            else{
                /* we would have overflowed -- set the overflow flag */
                flags |= FL_OVERFLOW;
                if(endptr == NULL) {
                    /* no need to keep on parsing if we
                       don't have to return the endptr. */
                    break;
                }
            }
 
            c = *p++;              /* read next digit */
        }
 
        --p;                           /* point to place that stopped scan */
 
        if(!(flags & FL_READDIGIT)) {
            /* no number there; return 0 and point to beginning of
               string */
            if(endptr)
                /* store beginning of string in endptr later on */
                p = nptr;
            number = 0L;           /* return 0 */
        }
        elseif ( (flags & FL_OVERFLOW) ||
                ( !(flags & FL_UNSIGNED) &&
                  ( ( (flags & FL_NEG) && (number > -LONG_MIN) ) ||
                    ( !(flags & FL_NEG) && (number > LONG_MAX) ) ) ) )
        {
            /* overflow or signed overflow occurred */
            errno= ERANGE;                  //(老的实现方式和新的实现方式区别主要在这里, 新版友记录转换过程)
            if( flags & FL_UNSIGNED )
                number = ULONG_MAX;
            elseif ( flags & FL_NEG )
                number = (unsignedlong)(-LONG_MIN);
            else
                number = LONG_MAX;
        }
 
        if(endptr != NULL)
            /* store pointer to char that stopped the scan */
            *endptr = p;
 
        if(flags & FL_NEG)
            /* negate result if there was a neg sign */
            number = (unsignedlong)(-(long)number);
 
        returnnumber;                  /* done. */
}

 

 

所以 atoi 已经等同于strtol 

Sign,  Clown , 2010.07.01 . 23:32 . HDPY

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