条件查询问题

$where   = array("usname"=>array('neq','1'));  //不等于

$map['status']   = array(in,"0,3"); //或者

//电话和用户名  都可以登陆的情况

$where['name']    =   I('post.username');
$where['mobile']   =  I('post.username');
$where['_logic']     = 'or';  //或者
$where['_complex'] = $map;  //合并$where['password'] = md5(I('post.password'));

$where['title']      = array('LIKE', '%'.$title.'%');  //模糊查询
$where['time'] = array('between' ，array($start_time,$end_time)); //在此之间
$where['time'] = array('gt'，'$start_time');  //大于。。。
$where['time'] = array( 'lt'，'$end_time');   //小于。。。