Distributing Parts CodeForces

You are an assistant director in a new musical play. The play consists of n musical parts, each part must be performed by exactly one actor. After the casting the director chosem actors who can take part in the play. Your task is to assign the parts to actors. However, there are several limitations.

First, each actor has a certain voice range and there are some parts that he cannot sing. Formally, there are two integers for each actor,c_i andd_i (c_i ≤ d_i) — the pitch of the lowest and the highest note that the actor can sing. There also are two integers for each part — a_j and b_j (a_j ≤ b_j) — the pitch of the lowest and the highest notes that are present in the part. The i-th actor can perform thej-th part if and only if c_i ≤ a_j ≤ b_j ≤ d_i, i.e. each note of the part is in the actor's voice range.

According to the contract, the i-th actor can perform at mostk_i parts. Besides, you are allowed not to give any part to some actors (then they take part in crowd scenes).

The rehearsal starts in two hours and you need to do the assignment quickly!

Input

The first line contains a single integer n — the number of parts in the play (1 ≤ n ≤ 10⁵).

Next n lines contain two space-separated integers each,a_j andb_j — the range of notes for thej-th part (1 ≤ a_j ≤ b_j ≤ 10⁹).

The next line contains a single integer m — the number of actors (1 ≤ m ≤ 10⁵).

Next m lines contain three space-separated integers each,c_i,d_i andk_i — the range of thei-th actor and the number of parts that he can perform (1 ≤ c_i ≤ d_i ≤ 10⁹,1 ≤ k_i ≤ 10⁹).

Output

If there is an assignment that meets all the criteria aboce, print a single word "YES" (without the quotes) in the first line.

In the next line print n space-separated integers. Thei-th integer should be the number of the actor who should perform thei-th part. If there are multiple correct assignments, print any of them.

If there is no correct assignment, print a single word "NO" (without the quotes).

Example

Input

31 32 43 521 4 22 5 1

Output

YES1 1 2

Input

31 32 43 521 3 22 5 1

Output

NO

题意：这里有一些歌剧和演员，每个演员有一个声域L，R，并且这个演员只可以出演k个歌剧，每个歌剧也需要一个声域至少覆盖L,R的演员才能出演，现在要求每个歌剧都要有一个演员去演请问该怎么分配，

第一眼看上去，我擦，网络流，二分图最大匹配，一看数据范围，发现不对了.......仔细想了想，是个贪心

思路如下：首先让歌剧和演员都按照他们的音域的R来排序，然后逐个考虑演员，把所有R小于当前考虑的演员的音域都加入set里面，然后找到L最接近演员L的，并让这个演员出演这个歌剧，如果找不到，就考虑下一个演员

代码如下：

#include <bits/stdc++.h>using namespace std;const int maxn = 1000005;struct node{    int l,r,pos,k;};node part[maxn],actor[maxn];bool cmp(node a,node b){    return a.r<b.r;}int ans[maxn];set<pair<int,int> >s;int main(){    s.clear();    memset(ans,0,sizeof(ans));    int n,m;    cin>>n;    for(int i=1;i<=n;i++){        scanf("%d%d",&part[i].l,&part[i].r);        part[i].pos=i;    }    cin>>m;    for(int i=1;i<=m;i++){        scanf("%d%d%d",&actor[i].l,&actor[i].r,&actor[i].k);        actor[i].pos=i;    }    sort(part+1,part+1+n,cmp);    sort(actor+1,actor+1+m,cmp);    int i=1,j=1,ok=0;    while(j<=m){        if(i<=n && part[i].r<=actor[j].r){            s.insert(make_pair(part[i].l,part[i].pos));            i++;        }        else{            set<pair<int,int> >::iterator it;            it=s.lower_bound(make_pair(actor[j].l,0));            if(it==s.end()){                if(j==m && s.size()>0){//如果s不为空，并且最后一个演员没有歌剧演说明扔到s里面的某些歌剧没人演                    ok=1;                    break;                }                else{                    j++;                    continue;                }            }            ans[it->second]=actor[j].pos;            s.erase(it);            actor[j].k--;            if(actor[j].k==0)j++;//只有当这个演员不能再用的时候再考虑下一个演员        }    }    for(int i=1;i<=n;i++)if(ans[i]==0)ok=1;    if(!ok){        cout<<"YES"<<endl;        cout<<ans[1];        for(int i=2;i<=n;i++)printf(" %d",ans[i]);        cout<<endl;    }    else{        cout<<"NO"<<endl;    }}