c++十进制转二进制

可以使用栈来做。

#include <iostream>#include <stack>using namespace std;int main(){int n,ans;cin>>n;stack<int> stk;while(n!=0){ans=n%2;n=n/2;stk.push(ans);}while(!stk.empty()){cout<<stk.top();stk.pop();}return 0;}

推广到任意进制
#include<iostream>#include<stack>#include<cmath>using namespace std;void convert(int num,int m){    char c[16]={'0','1','2','3','4','5','6','7','8','9','A','B','C','D','E','F'};    stack<char> s;    int n=abs(num);    while(n){        s.push(c[n%m]);        n/=m;    }    if(num>=0){        while(!s.empty()){         cout<<s.top();         s.pop();     }    }    else{        cout<<"-";        while(!s.empty()){         cout<<s.top();         s.pop();     }    }    }int main(){    int n,m;    cin>>n>>m;    convert(n,m);    return 0;}
方法2：
#include <iostream>#include <cmath>using namespace std;char numToChar(int n){    if(n<=9&&n>=0)        return n+'0';    if(n>9&&n<16)        return 'A'+(n-10);    return ' ';}int main(){    int num, k;    cin>>num>>k;    string ret="";    int n = abs(num);     while(n)        {        int left = n%k;        ret = numToChar(left)+ ret;        n/=k;    }    if(num<0)      ret = '-'+ret;      cout<<ret<<endl;    return 0;}