PHP get post json简单接口

来源：互联网发布：linux 文件夹映射编辑：程序博客网时间：2024/06/01 14:05

把文件放在服务器的响应目录下用浏览器访问即可：

GET:

<?php    $data = array(        'name' => '博客地址',        'site' => 'http://blog.csdn.net/ufo00001'    );    $response = array(        'code' => 200,        'message' => 'success',        'data' => $data,    );    echo json_encode($response);?>

POST:

<?php/** * code: 小程序发来的用户code * type: 1: android 2: ios */$code = $_POST['code'];$type = $_POST['type'];$data = '';if (isset($type)&& is_numeric($type) && $type >= 0) {    if ($type == 1) {        $data = array(            'type' => $type,            'name' => '安卓',            'code' => $code);    } else if ($type == 2) {        $data = array(            'type' => $type,            'name' => '苹果',            'code' => $code);    }else{        $data = array(            'alert' => 'type值只能为1或2 !',            );    }    $response = array(        'code' => 200,        'message' => 'success for request',        'data' => $data,    );    echo json_encode($response);    return;}    $response = array(        'code' => 1000,        'message' => 'argument error for request',    );    echo json_encode($response);?>

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