Random的nextInt(int i)方法的返回值

new Random().netxInt(int i)

public int nextInt(int n) {        if (n <= 0)            throw new IllegalArgumentException("n must be positive");        if ((n & -n) == n)  // i.e., n is a power of 2            return (int)((n * (long)next(31)) >> 31);        int bits, val;        do {            bits = next(31);            val = bits % n;        } while (bits - val + (n-1) < 0);        return val;    }

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docs中说返回值是从0到i，不够准确。
返回值应该是 >=0 , < i,就是说永远也不会返回i。

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来源
http://www.blogjava.net/mstar/archive/2005/05/21/5026.html

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