【Leetcode】【python】Pascal's Triangle, Pascal's Triangle II
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Pascal’s Triangle
题目大意
输出帕斯卡三角前N行
1
121
1331
解题思路
注意帕斯卡三角中,除了首尾,其他值为上一层的两个邻值的和
代码
class Solution(object): def generate(self, numRows): """ :type numRows: int :rtype: List[List[int]] """ if numRows == 0: return [] ans = [] for i in range(numRows): row = [] for j in range(i+1): row.append(1) if i > 1: for x in range(i - 1): row[x+1] = ans[i-1][x] + ans[i-1][x+1] print row ans.append(row) return ans
Pascal’s Triangle II
题目大意
只返回第n行
解题思路
同时注意与上题的下标起点不一样(rowIndex先加个1 = =)
代码
class Solution(object): def getRow(self, rowIndex): """ :type rowIndex: int :rtype: List[int] """ rowIndex += 1 ans = [] if rowIndex == 0: return [] for i in range(rowIndex): this = [] for j in range(i+1): this.append(1) if i > 1: for x in range(i - 1): this[x+1] = ans[i-1][x] + ans[i-1][x+1] print this ans.append(this) return ans[rowIndex - 1]
总结
帕斯卡三角, 我自己一开始试着写了一个函数
def get_num(i, j): # 三种特例,左边右边最上面 if i == j: return 1 if i == 0: return 1 if i > 0 and j == 0: return 1 # 输入有误返回False if i < j: return False else: return get_num(i - 1, j - 1) + get_num(i - 1, j)print(get_num(7, 2))
leetcode貌似并不能单独开函数。
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