485. Max Consecutive Ones
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题目来源【Leetcode】
Given a binary array, find the maximum number of consecutive 1s in this array.
Example 1:
Input: [1,1,0,1,1,1]
Output: 3
Explanation: The first two digits or the last three digits are consecutive 1s.
The maximum number of consecutive 1s is 3.Note:
The input array will only contain 0 and 1.
The length of input array is a positive integer and will not exceed 10,000
直接上代码:
class Solution {public: int findMaxConsecutiveOnes(vector<int>& nums) { int max_count = 0; int temp = 0; for(int i = 0; i < nums.size(); i++){ if(nums[i] == 1){ temp++; max_count = max(temp,max_count); } else{ temp = 0; } } return max_count; }};
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- 485. Max Consecutive Ones*
- 485. Max Consecutive Ones
- 485. Max Consecutive Ones
- 485. Max Consecutive Ones
- 485. Max Consecutive Ones
- 485. Max Consecutive Ones
- 485. Max Consecutive Ones
- 485. Max Consecutive Ones
- 485. Max Consecutive Ones
- 485. Max Consecutive Ones
- 485. Max Consecutive Ones
- 485. Max Consecutive Ones
- 485. Max Consecutive Ones
- 485. Max Consecutive Ones
- 485. Max Consecutive Ones
- 485. Max Consecutive Ones
- 485. Max Consecutive Ones
- 485.Max Consecutive Ones
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