逆置数组元素--reverse（）

整理一下见过的reverse方法。逆置数组元素中的值，例如，若x所指向的数组中的数据依次为9,8,7,6,5，则逆置后依次为：5,6,7,8,9

代码如下：

#include <stdio.h>  #include <conio.h>  #include <time.h>  void func1(int a[],int m)  {      int i,temp;      for (i = 0;i < m/2; i++)      {          temp = a[i];          a[i] = a[m-1-i];          a[m-1-i] = temp;      }  }  void func2(int a[],int m)  {      int i,j,temp;      for (i = 0,j = m-1;i < m/2; i++,j--)      {          temp = a[i];          a[i] = a[j];          a[j] = temp;      }  }  void func3(int a[],int m)  {      int temp,*p;      p = a+m-1;      for (;a < p; a++,p--)      {          temp = *a;          *a = *p;          *p = temp;      }  }  void main()  {      int i;      int x[] = {9,8,7,6,5};      int num1 = sizeof(x)/sizeof(x[0]);      //printf("%d",num);      printf("The original data is:\n");      for (i = 0;i < num1; i++)      {          printf(" %d",x[i]);      }      printf("\n");      printf("The answer of func1:\n");      func1(x,num1);      for (i = 0;i <num1; i++)      {          printf(" %d",x[i]);      }      printf("\n func1 is over !\n");      //func1 is over !      int y[] = {9,8,7,6,5};      int num2 = sizeof(y)/sizeof(y[0]);      printf("The answer of func2:\n");      func2(y,num2);      for (i = 0;i < num2; i++)      {          printf(" %d",y[i]);      }      printf("\n func2 is over !\n");      //func2 is over !      int z[] = {9,8,7,6,5};      int num3 = sizeof(z)/sizeof(z[0]);      printf("The answer of func3:\n");      func3(z,num3);      for (i = 0;i < num3; i++)      {          printf(" %d",z[i]);      }      printf("\n func3 is over !\n");      //func3 is over !      getch();  }