Ducci 队列
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A Ducci sequence is a sequence of n-tuples of integers. Given an n-tuple of integers (a1, a2, · · · , an),the next n-tuple in the sequence is formed by taking the absolute differences of neighboring integers:(a1, a2, · · · , an) → (|a1 − a2|, |a2 − a3|, · · · , |an − a1|)Ducci sequences either reach a tuple of zeros or fall into a periodic loop. For example, the 4-tuplesequence starting with 8,11,2,7 takes 5 steps to reach the zeros tuple:(8, 11, 2, 7) → (3, 9, 5, 1) → (6, 4, 4, 2) → (2, 0, 2, 4) → (2, 2, 2, 2) → (0, 0, 0, 0).The 5-tuple sequence starting with 4,2,0,2,0 enters a loop after 2 steps:(4, 2, 0, 2, 0) → (2, 2, 2, 2, 4) → (0,0,0,2,2) → (0, 0, 2, 0, 2) → (0, 2, 2, 2, 2) → (2, 0, 0, 0, 2) →(2, 0, 0, 2, 0) → (2, 0, 2, 2, 2) → (2, 2, 0, 0, 0) → (0, 2, 0, 0, 2) → (2, 2, 0, 2, 2) → (0, 2, 2, 0, 0) →(2, 0, 2, 0, 0) → (2, 2, 2, 0, 2) → (0, 0, 2, 2, 0) → (0, 2, 0, 2, 0) → (2, 2, 2, 2, 0) → (0,0,0,2,2) → · · ·Given an n-tuple of integers, write a program to decide if the sequence is reaching to a zeros tupleor a periodic loop.InputYour program is to read the input from standard input. The input consists of T test cases. The numberof test cases T is given in the first line of the input. Each test case starts with a line containing aninteger n (3 ≤ n ≤ 15), which represents the size of a tuple in the Ducci sequences. In the followingline, n integers are given which represents the n-tuple of integers. The range of integers are from 0 to1,000. You may assume that the maximum number of steps of a Ducci sequence reaching zeros tupleor making a loop does not exceed 1,000.OutputYour program is to write to standard output. Print exactly one line for each test case. Print ‘LOOP’ ifthe Ducci sequence falls into a periodic loop, print ‘ZERO’ if the Ducci sequence reaches to a zeros tuple.
Sample Input4
4
8 11 2 7
5
4 2 0 2 0
7
0 0 0 0 0 0 0
6
1 2 3 1 2 3
Sample Output
ZERO
LOOP
ZERO
LOOP
题意:有一个数组,判断是否可以通过变化变成全0;可以的话输出ZERO,否则输出LOOP
#include <cstdio>#include <string>#include <queue>#include <cmath>using namespace std;int main(){ int t,n; int a[16]; scanf("%d",&t); queue<int> Q; while(t--) { while(!Q.empty()) Q.pop(); scanf("%d",&n); for(int i=0; i<n; i++) { scanf("%d",&a[i]); Q.push(a[i]); } int head,first,second,num=0,ok=0; while(num++<1000&&!Q.empty()) { if(!ok) { head=Q.front(); ok=1; } first=Q.front();// printf("%d\n",head);// if(num==16)// break; Q.pop(); second=Q.front(); if(num%n==0) { first=abs(head-first); ok=0; } else first=abs(second-first); Q.push(first); } int sum=0; while(!Q.empty()) { sum+=Q.front(); Q.pop(); } if(!sum) printf("ZERO\n"); else printf("LOOP\n"); } return 0;}
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