First Position Unique Character
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Given a string, find the first non-repeating character in it and return it's index. If it doesn't exist, return -1
.
样例
Given s = "lintcode"
, return 0
.
Given s = "lovelintcode"
, return 2
.
public int firstUniqChar(String s) { int[] map = new int[200]; for (int i = 0; i < s.length(); i++) { char c = s.charAt(i); map[c]++; } for (int i = 0; i < s.length(); i++) { char c = s.charAt(i); if (map[c] == 1) return i; } return -1; }
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