php_lang_ref:Language Reference >> References Explained >> What References Are Not
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<?php// +----------------------------------------------------------------------// | Created by im-server.// +----------------------------------------------------------------------// | Language Reference >> References Explained >> What References Are Not// +----------------------------------------------------------------------// | Author: alexander <gt199899@gmail.com>// +----------------------------------------------------------------------// | Datetime: 2017-07-16 17:30// +----------------------------------------------------------------------// | Perfect Is Shit// +----------------------------------------------------------------------/** * 引用不是指针,所以不能实现case1中的情况; * case1 * case2 */namespace case1;function foo(&$var){ $var = &$GLOBALS["baz"]; return $var;}$baz = 0;$bar = 1;$foo = foo($bar);var_dump($foo);/** * 分析上面代码 * 第一步:$bar通过引用传递到函数foo中的$var,所以$bar和$var指向同一个内容; * 第二步:函数foo中的$var又和$GLOBALS["baz"]指向同一个内容,此时$var的值变为0; * 原因为 * 输出: * int(0) */namespace case2;function foo(&$var){ $GLOBALS["baz"] = &$var; return $var;}$baz = 0;$bar = 1;$foo = foo($bar);var_dump($baz);/** * 将$GLOBALS["baz"]和$var都指向了$var的内容,所以输出为$bar的内容1; * 输出: * int(1) */
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