leetcode 24. Swap Nodes in Pairs

来源:互联网 发布:keras 安装 windows 编辑:程序博客网 时间:2024/06/16 12:21

Given a linked list, swap every two adjacent nodes and return its head.

For example,
Given 1->2->3->4, you should return the list as 2->1->4->3.

Your algorithm should use only constant space. You may not modify the values in the list, only nodes itself can be changed.

解:迭代的思想

/** * Definition for singly-linked list. * struct ListNode { *     int val; *     ListNode *next; *     ListNode(int x) : val(x), next(NULL) {} * }; */class Solution {public:    ListNode* swapPairs(ListNode* head) {        if(head){            if(head->next){                ListNode* tmp = head->next;                head->next = swapPairs(tmp->next);                tmp->next = head;                return  tmp;            }else return head;        }else return head;    }};

原创粉丝点击