POJ 1008--Maya Calendar

题意

题目的意思是，有两种日历，第一种称为Haab，一年为365天，一年19个月，前18个月每个月20天，第19个月为5天，每个月的名字分别为pop, no, zip, zotz, tzec, xul, yoxkin, mol, chen, yax, zac, ceh, mac, kankin, muan, pax, koyab, cumhu和uayet，每个月份中的天数用0到19表示。最后一个月份中的天数用0到4表示。第二个日历称为Tzolkin，在这个日历中，一年为260天，一年分为13段，每段20天（260=13*20），每一天用一个数字和一个名字表示，总共20个名字： imix, ik, akbal, kan, chicchan, cimi, manik, lamat, muluk, ok, chuen, eb, ben, ix, mem, cib, caban, eznab, canac, ahau，数字为1到13，数字和名字都顺序循环，例如，第一年开始的几天为：1 imix, 2 ik, 3 akbal, 4 kan, 5 chicchan, 6 cimi, 7 manik, 8 lamat, 9 muluk, 10 ok, 11 chuen, 12 eb, 13 ben, 1 ix, 2 mem, 3 cib, 4 caban, 5 eznab, 6 canac, 7 ahau, 然后进入下一段 8 imix, 9 ik, 10 akbal。

分析

把输入的Haab日期转换为Tzolkin日历，简单的映射一下即可，代码如下：

Memory: 264K Time: 0MS Length：29LINES

#include<iostream>#include<map>#include<string>using namespace std;int main(){    map<string, int> Haab;  //日历的映射    Haab["uayet"] = 18; Haab["cumhu"] = 17; Haab["koyab"] = 16; Haab["pax"] = 15; Haab["muan"] = 14; Haab["kankin"] = 13; Haab["mac"] = 12;    Haab["ceh"] = 11; Haab["zac"] = 10; Haab["yax"] = 9; Haab["chen"] = 8; Haab["mol"] = 7; Haab["yoxkin"] = 6; Haab["xul"] = 5;    Haab["tzec"] = 4; Haab["zotz"] =  3; Haab["zip"] = 2; Haab["no"] = 1; Haab["pop"] = 0;      string Tzolkin[20];    Tzolkin[0] = "imix"; Tzolkin[1] = "ik"; Tzolkin[2] = "akbal"; Tzolkin[3] = "kan"; Tzolkin[4] = "chicchan"; Tzolkin[5] = "cimi";    Tzolkin[6] = "manik"; Tzolkin[7] = "lamat"; Tzolkin[8] = "muluk"; Tzolkin[9] = "ok"; Tzolkin[10] = "chuen"; Tzolkin[11] = "eb";    Tzolkin[12] = "ben"; Tzolkin[13] = "ix"; Tzolkin[14] = "mem"; Tzolkin[15] = "cib"; Tzolkin[16] = "caban"; Tzolkin[17] = "eznab";    Tzolkin[18] = "canac"; Tzolkin[19] = "ahau";    int count = 0;    cin >> count;    float days = 0;    string month;    int years = 0;    cout << count << endl;    int tmp;    while (cin >> days >> month >> years)    {           tmp = 365 * years + 20 * Haab[month] + (int)days;        cout << tmp % 13 + 1 << " " << Tzolkin[tmp % 20] << " " << tmp / 260 << endl;    }    return 0;}