Python如何将列表分成均匀大小的块？

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均匀大小的块

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def chunks(l, n):    """Yield successive n-sized chunks from l."""    for i in range(0, len(l), n):        yield l[i:i + n]

import pprintpprint.pprint(list(chunks(range(10, 75), 10)))[[10, 11, 12, 13, 14, 15, 16, 17, 18, 19], [20, 21, 22, 23, 24, 25, 26, 27, 28, 29], [30, 31, 32, 33, 34, 35, 36, 37, 38, 39], [40, 41, 42, 43, 44, 45, 46, 47, 48, 49], [50, 51, 52, 53, 54, 55, 56, 57, 58, 59], [60, 61, 62, 63, 64, 65, 66, 67, 68, 69], [70, 71, 72, 73, 74]]

#python3[l[i:i + n] for i in range(0, len(l), n)]

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参考文献

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How do you split a list into evenly sized chunks?