CodeForces

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B. Karen and Coffee
time limit per test
2.5 seconds
memory limit per test
512 megabytes
input
standard input
output
standard output

To stay woke and attentive during classes, Karen needs some coffee!

Karen, a coffee aficionado, wants to know the optimal temperature for brewing the perfect cup of coffee. Indeed, she has spent some time reading several recipe books, including the universally acclaimed "The Art of the Covfefe".

She knows n coffee recipes. The i-th recipe suggests that coffee should be brewed between li and ri degrees, inclusive, to achieve the optimal taste.

Karen thinks that a temperature is admissible if at least k recipes recommend it.

Karen has a rather fickle mind, and so she asks q questions. In each question, given that she only wants to prepare coffee with a temperature between a and b, inclusive, can you tell her how many admissible integer temperatures fall within the range?

Input

The first line of input contains three integers, nk (1 ≤ k ≤ n ≤ 200000), and q (1 ≤ q ≤ 200000), the number of recipes, the minimum number of recipes a certain temperature must be recommended by to be admissible, and the number of questions Karen has, respectively.

The next n lines describe the recipes. Specifically, the i-th line among these contains two integers li and ri (1 ≤ li ≤ ri ≤ 200000), describing that the i-th recipe suggests that the coffee be brewed between li and ri degrees, inclusive.

The next q lines describe the questions. Each of these lines contains a and b, (1 ≤ a ≤ b ≤ 200000), describing that she wants to know the number of admissible integer temperatures between a and b degrees, inclusive.

Output

For each question, output a single integer on a line by itself, the number of admissible integer temperatures between a and b degrees, inclusive.

Examples
input
3 2 491 9492 9797 9992 9493 9795 9690 100
output
3304
input
2 1 11 1200000 20000090 100
output
0
Note

In the first test case, Karen knows 3 recipes.

  1. The first one recommends brewing the coffee between 91 and 94 degrees, inclusive.
  2. The second one recommends brewing the coffee between 92 and 97 degrees, inclusive.
  3. The third one recommends brewing the coffee between 97 and 99 degrees, inclusive.

A temperature is admissible if at least 2 recipes recommend it.

She asks 4 questions.

In her first question, she wants to know the number of admissible integer temperatures between 92 and 94 degrees, inclusive. There are 39293 and 94 degrees are all admissible.

In her second question, she wants to know the number of admissible integer temperatures between 93 and 97 degrees, inclusive. There are 39394 and 97 degrees are all admissible.

In her third question, she wants to know the number of admissible integer temperatures between 95 and 96 degrees, inclusive. There are none.

In her final question, she wants to know the number of admissible integer temperatures between 90 and 100 degrees, inclusive. There are 4929394 and 97 degrees are all admissible.

In the second test case, Karen knows 2 recipes.

  1. The first one, "wikiHow to make Cold Brew Coffee", recommends brewing the coffee at exactly 1 degree.
  2. The second one, "What good is coffee that isn't brewed at at least 36.3306 times the temperature of the surface of the sun?", recommends brewing the coffee at exactly 200000 degrees.

A temperature is admissible if at least 1 recipe recommends it.

In her first and only question, she wants to know the number of admissible integer temperatures that are actually reasonable. There are none.


题意:求指定区间内出现K次的数的个数

前缀和。

创建一个初始全为0的数组a,所给条件的区间[l,r],另a[l]++,a[r+1]--,然后对数组a求前缀和。

创建一个初始全为0的数组sum,如果第i位前缀和大于等于k,sum[i++].对sum求前缀和。

若询问[l,r]中满足条件的个数,答案即为sum[r]-sum[l-1];

#include<iostream>#include<stdio.h>#include<stdlib.h>#define maxn 200001using namespace std;int main(){    int n,k,q,a[maxn],sum[maxn];    while(scanf("%d%d%d",&n,&k,&q)!=EOF)    {        fill(a,a+maxn,0);        fill(sum,sum+maxn,0);        int l,r,i;        for(i=0;i<n;i++)        {            scanf("%d%d",&l,&r);            a[l]++;            a[r+1]--;        }        for(i=1;i<maxn;i++)        {            a[i]=a[i-1]+a[i];            if(a[i]>=k)                sum[i]++;        }        for(i=1;i<maxn;i++)        {            sum[i]=sum[i-1]+sum[i];        }        while(q--)        {            int ans=0;            scanf("%d%d",&l,&r);            printf("%d\n",sum[r]-sum[l-1]);        }    }}

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