Android笔记（18）再按一次退出程序

private long exitTime = 0;@Overridepublic boolean onKeyDown(int keyCode, KeyEvent event) {    if(keyCode == KeyEvent.KEYCODE_BACK && event.getAction() == KeyEvent.ACTION_DOWN){           if((System.currentTimeMillis()-exitTime) > 2000){              Toast.makeText(getApplicationContext(), "再按一次退出程序", Toast.LENGTH_SHORT).show();                                            exitTime = System.currentTimeMillis();           } else {            finish();            System.exit(0);        }        return true;       }    return super.onKeyDown(keyCode, event);}