PAT a1058题解

来源:互联网 发布:数据库编程语言 编辑:程序博客网 时间:2024/06/05 09:42
#include <cstdio>int main(){long long gallon1, sickle1, knuts1;long long gallon2, sickle2, knuts2;long long gallon3, sickle3, knuts3;int temp1 = 0, temp2 = 0;scanf("%lld.%lld.%lld %lld.%lld.%lld", &gallon1, &sickle1, &knuts1, &gallon2, &sickle2, &knuts2);if(knuts1 + knuts2 >= 29){knuts3 = (knuts1 + knuts2) % 29;temp1 = 1;}else{knuts3 = knuts1 + knuts2;}if(sickle1 + sickle2 + temp1 >= 17){sickle3 = (sickle1 + sickle2 + temp1) % 17;temp2 = 1;} else{sickle3 = sickle1 + sickle2 + temp1;}gallon3 = gallon1 + gallon2 + temp2;printf("%lld.%lld.%lld", gallon3, sickle3, knuts3);return 0;}

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