Java-10-50的随机数，统计出现的次数

随机产生50个10到50的整数，统计每个数字各出现几次，出现0次的数字不打印。

代码如下：

package com.homework.lhh;import java.util.Random;public class Ex04 {    public static void main(String[] args) {        int[] array = new int[50];        Random random = new Random();        for (int i = 0; i < array.length; i++) {            array[i] = random.nextInt(41) + 10;            System.out.print(array[i] + " ");        }        for (int i = 0; i < array.length - 1; i++) {            for (int j = 0; j < array.length - i - 1; j++) {                if (array[j] > array[j + 1]) {                    int tmp = array[j];                    array[j] = array[j + 1];                    array[j + 1] = tmp;                }            }        }        System.out.println();        //为了方便直观的统计        System.out.println("冒泡排序后的数组为：");        for (int i = 0; i < array.length; i++) {            System.out.print(array[i] + " ");        }        /*         * for (int i = 0; i < array.length; i++) { if(0 == array[i]){ continue;         * } if(array[i] == array[i+1]){ conut++; } System.out.println();         * System.out.print( array[i] + "出现的次数为："+ (conut+1) +" 次"); conut = 0;         * }         */        // 查找        System.out.println();        for (int i = 0; i < array.length; i++) {            int conut = 0;// 定义每一个数出现的次数            for (int j = 0; j < array.length; j++) {                if (array[i] == array[j]) {                    conut++;                }            }            if (i < 49 && array[i] != array[i + 1] && conut != 0) {                System.out.println(array[i] + "出现的次数为：" + conut + " 次");            }            if(i == 49){                System.out.println(array[i] + "出现的次数为：" + conut + " 次");            }        }    }}

运行结果如下：