PAT(Basic Level)_1011_A+B和C
来源:互联网 发布:固定循环编程注意? 编辑:程序博客网 时间:2024/05/29 19:46
#include<stdio.h>int main(){ int T; long A,B,C; scanf("%d",&T); for(int i=1;i<=T;i++){ scanf("%ld%ld%ld",&A,&B,&C); printf("Case #%d: ",i); if(A+B>C) printf("true\n"); else printf("false\n"); } return 0;}
阅读全文
0 0
- PAT(Basic Level)_1011_A+B和C
- PAT(Basic Level):A+B和C
- PAT.Basic Level. A+B和C
- Pat(Basic Level)Practice--1011(A+B和C)
- PAT Basic Level 1011. A+B和C(15)
- 【PAT 乙级(Basic Level)】A+B和C
- PAT (Basic Level)1011. A+B和C
- PAT BASIC LEVEL 1011. A+B和C (15)
- 【C++】浙大PAT (Basic Level)1011. A+B和C (15)
- PAT (Basic Level) Practise (中文)1011. A+B和C (15) C语言
- PAT (Basic Level) Practise (中文)1011. A+B和C (15)
- PAT乙级(Basic Level)真题 >A+B和C (15)
- PAT (Basic Level) Practise (中文)1011. A+B和C (15)
- 【C++】浙大PAT (Basic Level)1016. 部分A+B (15)
- 【C++】浙大PAT (Basic Level)1017. A除以B (20)
- PAT basic 1011 : A+B 和 C
- 1011. A+B和C(PAT Basic)
- 【PAT 乙级(Basic Level)】分A+B
- Struts2笔记
- 安装 Docker Machine
- 树链剖分模板
- Codeforces 447B DZY Loves Strings
- Alignment of Code
- PAT(Basic Level)_1011_A+B和C
- xgb原理及使用
- Centos下修改mysql的默认编码方式
- PAT(Basic Level)_1012_数字分类
- Ducci Sequence
- java中的迭代器模式
- oracle常用
- [模板]manacher算法
- Digital Roots