[杂题] Codechef July Challenge 2017 #MULDIG Multiplication Program
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大意是把二元运算化成一元运算
感谢sxt的帮助
剩下的看代码注释吧 //我觉得蛮清楚了
唯一不爽的是 没想到临时变量这么多 mmp
#include<cstdio>#include<cstdlib>#include<algorithm>#include<vector>#define pb push_backusing namespace std;int B;struct abcd{ int x,y,z; abcd(int x=0,int y=0,int z=0):x(x),y(y),z(z) { }};//int f[100005];int a[10][10];#define t1 (B+100)#define t2 (B+101)#define t3 (B+102) #define t4 (B+103)#define t5 (B+104)#define t6 (B+105)#define t7 (B+106)#define t8 (B+107)#define t9 (B+108)#define t10 (B+109)#define t (B+110)vector<abcd> Ans;inline void P(int x,int y,int z){ Ans.pb(abcd(x,y,z)); //f[z]=a[f[x]][f[y]];}inline void cpy(int y,int x){ //y=x; P(0,x,y);}inline void _not(int y,int x){ //y=!x P(2,x,y);}inline void _bool(int a,int b){ //a=(bool)b _not(a,b); _not(a,a);}inline void add(int x){ //x++ P(1,x,x);}inline void _and(int z,int x,int y){ //z=x&&y P(x,y,z); for (int i=1;i<=B-2;i++) add(z); _not(z,z);}inline void del(int x){ //x-- for (int i=1;i<B;i++) add(x);}inline void padd(int a,int b){ //if (a) b++; P(a,b,b);}inline void pdel(int a,int b){ //if (a) b--; cpy(t7,a); a=t7; for (int i=1;i<B;i++) P(a,b,b);}inline void pcpy(int a,int y,int x){ //if (a) y=x; cpy(t5,x); x=t5; cpy(t6,a); a=t6; cpy(t10,0); for (int i=0;i<B;i++){ _bool(t4,x); _and(t4,a,t4); padd(t4,t10); pdel(t4,x); } x=y; _not(a,a); for (int i=0;i<B;i++){ _bool(t4,x); _and(t4,a,t4); padd(t4,t10); pdel(t4,x); } cpy(y,t10);}inline void add(int a,int b,int c,int d){ /* c=b; for (int i=0;i<B;i++) if (a){ c++; if (a&&!c) d++; a--; } */ cpy(c,b); for (int i=0;i<B;i++){ _bool(t1,a); padd(t1,c); _not(t2,c); _and(t2,t1,t2); padd(t2,d); pdel(t1,a); }}inline void mul(int a,int b,int c,int d){ /* t=b; for (int i=0;i<(B-1)*(B-1);i++){ if (a&&t){ c++; if (a&&t&&!c) d++; t--; } if (a&&!t) a--,t=b; } */ cpy(t8,a); a=t8; cpy(t9,b); b=t9; cpy(t,b); for (int i=0;i<(B-1)*(B-1);i++){ _bool(t1,a); _bool(t2,t); _and(t1,t1,t2); padd(t1,c); _not(t3,c); _and(t3,t1,t3); padd(t3,d); pdel(t1,t); _bool(t1,a); _not(t2,t); _and(t1,t1,t2); pdel(t1,a); pcpy(t1,t,b); }}#define C B#define D B+1#define E B+2#define F B+3#define G B+4#define H B+5#define I B+6#define J B+7#define T1 B+8#define T2 B+9#define T3 B+10#define T4 B+11#define T5 B+12#define T6 B+13#define T7 B+14#define T8 B+15#define T9 B+16#define T10 B+17#define T11 B+18#define T12 B+19#define T13 B+20#define T14 B+21#define T15 B+22#define T16 B+23#define T17 B+24#define T18 B+25#define T19 B+26#define T20 B+27#define T21 B+28#define T22 B+29#define T23 B+30#define T24 B+31#define T25 B+32#define T26 B+33#define trash B+1000inline void Solve(){ for (int i=0;i<B;i++) a[0][i]=i,a[1][i]=(i+1)%B; a[2][0]=1; for (int i=0;i<B;i++,putchar('\n')) for (int j=0;j<B;j++) printf("%d ",a[i][j]); mul(D,F,J,T1); mul(C,F,T3,T4); mul(E,D,T5,T6); add(T3,T5,T7,T8); add(T7,T1,I,T10); mul(E,C,T11,T12); add(T11,T4,T13,T14); add(T13,T6,T15,T16); add(T15,T8,T17,T18); add(T17,T10,H,T20); add(T12,T14,T21,trash); add(T21,T16,T22,trash); add(T22,T18,T23,trash); add(T23,T20,G,trash); printf("%d\n",Ans.size()); for (abcd x:Ans) printf("%d %d %d\n",x.x,x.y,x.z);}int main(){ freopen("t.in","r",stdin); freopen("t.out","w",stdout); scanf("%d",&B); /*int _C,_D,_E,_F; scanf("%d%d%d%d",&_C,&_D,&_E,&_F); for (int i=0;i<B;i++) f[i]=i; f[B]=_C; f[B+1]=_D; f[B+2]=_E; f[B+3]=_F;*/ Solve(); return 0;}
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