poj2080--算日期

题意：起始日期为2001-1-1，求过了那天后的日期还有那天是周几。

思路：最重要的是判断闰年，加一个判断函数，之后周几对7取余数就知道了。

#include <iostream>using namespace std; int mon[2][13]={0,31,28,31,30,31,30,31,31,30,31,30,31,0,31,29,31,30,31,30,31,31,30,31,30,31};int yea[2]={365,366};int n;char zhou[7][15]={"Saturday","Sunday","Monday", "Tuesday", "Wednesday", "Thursday", "Friday"};/* run this program using the console pauser or add your own getch, system("pause") or input loop */int judge(int y){if((y%400==0)||(y%4==0&&y%100!=0))return 1;else return 0;}int main(int argc, char** argv) {while(cin>>n&&n!=-1){int i,j,day=1;int ff=n%7;for(i=2000;n>=yea[judge(i)];i++)n-=yea[judge(i)];int tt=judge(i);for(j=1;n>=mon[tt][j];j++)n-=mon[tt][j];day+=n;printf("%d-%02d-%02d %s\n",i,j,day,zhou[ff]);} return 0;}