CodeForces

B. The Same Calendar

time limit per test

1 second

memory limit per test

256 megabytes

input

standard input

output

standard output

The girl Taylor has a beautiful calendar for the year y. In the calendar all days are given with their days of week: Monday, Tuesday, Wednesday, Thursday, Friday, Saturday and Sunday.

The calendar is so beautiful that she wants to know what is the next year after y when the calendar will be exactly the same. Help Taylor to find that year.

Note that leap years has 366 days. The year is leap if it is divisible by 400 or it is divisible by 4, but not by 100(https://en.wikipedia.org/wiki/Leap_year).

Input

The only line contains integer y (1000 ≤ y < 100'000) — the year of the calendar.

Output

Print the only integer y' — the next year after y when the calendar will be the same. Note that you should find the first year after y with the same calendar.

Examples

input

2016

output

2044

input

2000

output

2028

input

50501

output

50507

题意：找出下一个年份跟今年相同的
平年（365 % 7 == 1）闰年（366 % 7 == 2），所以满足条件的下个年份就是能被7整除且跟今年是相同的闰年或平年。

AC代码：

#include<cstdio>int is_ren(int n){if(n%400 == 0 || (n%100 != 0 && n%4 == 0)) return 1;return 0;}int main(){int n, sum = 0, flag = 1;scanf("%d", &n);if(is_ren(n)){flag = 0;}for(int i = n + 1; i < n + 50; i++){if(is_ren(i)){sum = (sum + 366) % 7;}else{sum = (sum + 365) % 7;}if(sum == 0 && is_ren(i) == is_ren(n)){printf("%d", i);break;}}return 0;}