codeforces 719A Vitya in the Countryside

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A. Vitya in the Countryside

time limit per test

1 second

memory limit per test

256 megabytes

input

standard input

output

standard output

Every summer Vitya comes to visit his grandmother in the countryside. This summer, he got a huge wart. Every grandma knows that one should treat warts when the moon goes down. Thus, Vitya has to catch the moment when the moon is down.

Moon cycle lasts 30 days. The size of the visible part of the moon (in Vitya's units) for each day is 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 14, 13, 12, 11, 10, 9, 8, 7, 6, 5, 4, 3, 2, 1, and then cycle repeats, thus after the second 1 again goes 0.

As there is no internet in the countryside, Vitya has been watching the moon for n consecutive days and for each of these days he wrote down the size of the visible part of the moon. Help him find out whether the moon will be up or down next day, or this cannot be determined by the data he has.

Input

The first line of the input contains a single integer n (1 ≤ n ≤ 92) — the number of consecutive days Vitya was watching the size of the visible part of the moon.

The second line contains n integers ai (0 ≤ ai ≤ 15) — Vitya's records.

It's guaranteed that the input data is consistent.

Output

If Vitya can be sure that the size of visible part of the moon on day n + 1 will be less than the size of the visible part on day n, then print "DOWN" at the only line of the output. If he might be sure that the size of the visible part will increase, then print "UP". If it's impossible to determine what exactly will happen with the moon, print -1.

Examples

input

53 4 5 6 7

output

UP

input

712 13 14 15 14 13 12

output

DOWN

input

18

output

-1

Note

In the first sample, the size of the moon on the next day will be equal to 8, thus the answer is "UP".

In the second sample, the size of the moon on the next day will be 11, thus the answer is "DOWN".

In the third sample, there is no way to determine whether the size of the moon on the next day will be 7 or 9, thus the answer is -1.

题意：判断下一个值是上升还是下降，不能判断输出-1，分析最后两位，找特殊，剩下的就符合常规了。

#include<stdio.h>#include<stdlib.h>int main(){    int n,s[100];    scanf("%d",&n);    for(int i=0; i<n; i++)    {        scanf("%d",&s[i]);    }    if(n==1)    {        if(s[0]==15)            printf("DOWN\n");        else if(s[0]==0)            printf("UP\n");        else            printf("-1\n");    }    else    {        if(s[n-2]==14&&s[n-1]==15)        {            printf("DOWN\n");            return 0;        }        if(s[n-2]==1&&s[n-1]==0)        {            printf("UP\n");            return 0;        }        if(s[n-2]<s[n-1])        {            printf("UP\n");            return 0;        }        else        {            printf("DOWN\n");            return 0;        }    }    return 0;}