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A tennis tournament with n participants is running. The participants are playing by an olympic system, so the winners move on and the losers drop out.

The tournament takes place in the following way (below, m is the number of the participants of the current round):

• let k be the maximal power of the number 2 such that k ≤ m,
• k participants compete in the current round and a half of them passes to the next round, the other m - k participants pass to the next round directly,
• when only one participant remains, the tournament finishes.

Each match requires b bottles of water for each participant and one bottle for the judge. Besides p towels are given to each participant for the whole tournament.

Find the number of bottles and towels needed for the tournament.

Note that it's a tennis tournament so in each match two participants compete (one of them will win and the other will lose).

Input

The only line contains three integers n, b, p (1 ≤ n, b, p ≤ 500) — the number of participants and the parameters described in the problem statement.

Output

Print two integers x and y — the number of bottles and towels need for the tournament.

Examples

input

5 2 3

output

20 15

input

8 2 4

output

35 32

题意：有n个人打兵乓球比赛，两个人一组，赢的人直接晋级，输的淘汰，人数是奇数的时候剩下的一个人直接晋级。每组的每个运动员可以得到b瓶水，p个毛巾，裁判在每组比赛中得1瓶水，裁判没毛巾。问：共需多少瓶水，多少毛巾？？？
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人    数   | 2 | 3 | 4 | 5 | 6 |7
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比赛次数| 1 | 2 | 3 | 4 | 5 |6
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找出规律n个人打（n-1）场比赛，所以
水需要（n-1）+ (n-1)*2*b；
毛巾需要n*p；

AC代码：

#include<stdio.h>  #include<cstring>  #include<algorithm>  #define AC main()  using namespace std;  const int MYDD = 1103;    int AC {      int n, b, q;      scanf("%d %d %d", &n, &b, &q);      printf("%d %d\n", (n - 1) * (2*b + 1), n*q);      return 0;  }