poj1163

来源:互联网 发布:坎昆离墨西哥城源码 编辑:程序博客网 时间:2024/06/08 09:17
The Triangle
Time Limit: 1000MS Memory Limit: 10000KTotal Submissions: 50203 Accepted: 30341

Description

73   88   1   02   7   4   44   5   2   6   5(Figure 1)
Figure 1 shows a number triangle. Write a program that calculates the highest sum of numbers passed on a route that starts at the top and ends somewhere on the base. Each step can go either diagonally down to the left or diagonally down to the right. 

Input

Your program is to read from standard input. The first line contains one integer N: the number of rows in the triangle. The following N lines describe the data of the triangle. The number of rows in the triangle is > 1 but <= 100. The numbers in the triangle, all integers, are between 0 and 99.

Output

Your program is to write to standard output. The highest sum is written as an integer.

Sample Input

573 88 1 0 2 7 4 44 5 2 6 5

Sample Output

30


动态规划及空间优化

AC代码:

#include<iostream>
#include<algorithm>
#include<stdio.h>
using namespace std;
const int maxn=101;
int a[maxn][maxn];
int maxsum[maxn];
int main()
{
        int n;
        scanf("%d",&n);
        for(int i=1;i<=n;i++)
        for(int j=1;j<=i;j++)
                scanf("%d",&a[i][j]);
        for(int i=1;i<=n;i++)
                maxsum[i]=a[n][i];
        for(int i=n-1;i>=1;i--)
                for(int j=1;j<=i;j++)
                maxsum[j]=max(maxsum[j],maxsum[j+1])+a[i][j];
        printf("%d\n",maxsum[1]);
        return 0;
}