14.5 结构和其他数据形式：传递结构

来源：互联网发布：虚拟机安装nginx 编辑：程序博客网时间：2024/05/29 09:59

输出示例

please enter your first name:wangplease enter your last name:feiwang fei , your name contains 7 letters.

【结构作为参数传递并返回结构】

#include<stdio.h>#include<string.h>#define NLEN 30struct namect {    char fname[NLEN];    char lname[NLEN];    int letters;};struct namect getinfo(void);struct namect makeinfo(struct namect);void showinfo(struct namect);char *s_gets(char *st, int n);int main(){    struct namect person;    person = getinfo();    person = makeinfo(person);    showinfo(person);    return 0;}struct namect getinfo(void){    struct namect temp;    printf("please enter your first name:\n");    s_gets(temp.fname,NLEN);    printf("please enter your last name:\n");    s_gets(temp.lname, NLEN);    return temp;}//将结构person作为参数，创建一个新的结构info并将person的值拷贝到此结构struct namect makeinfo(struct namect info){    info.letters = strlen(info.fname) + strlen(info.lname);    //统计完字母个数后，结果保存在info中，通过return 将info的值拷贝到person中，即返回一个结构    return info;}void showinfo(struct namect info){    printf("%s %s , your name contains %d letters.\n", info.fname, info.lname, info.letters);}char *s_gets(char *st, int n){    char * ret_val;    char * find;    ret_val = fgets(st, n, stdin);    if (ret_val)    {        find = strchr(st, '\n');        if (find)            *find = '\0';        else            while (getchar() != '\n')                continue;    }    return ret_val;}

【传递结构的地址】

#include<stdio.h>#include<string.h>#define NLEN 30struct namect {    char fname[NLEN];    char lname[NLEN];    int letters;};void getinfo(struct namect *);void makeinfo(struct namect *);void showinfo(const struct namect *);char *s_gets(char * st, int n);int main(){    struct namect person;    getinfo(&person);    makeinfo(&person);    showinfo(&person);    getchar();    return 0;}void getinfo(struct namect * pst){    printf("please enter your first name .\n");    s_gets(pst->fname,NLEN);    printf("please enter your last name.\n");    s_gets(pst->lname, NLEN);}void makeinfo(struct namect *pst){    pst->letters = strlen(pst->fname) + strlen(pst->lname);}void showinfo(const struct namect *pst){    printf("%s %s,your name contains %d letters .\n",pst->fname,pst->lname,pst->letters);}char *s_gets(char *st, int n){    char * ret_val;    char * find;    ret_val = fgets(st, n, stdin);    if (ret_val)    {        find = strchr(st, '\n');        if (find)            *find = '\0';        else            while (getchar() != '\n')                continue;    }    return ret_val;}

阅读全文

0 0