WERTYU
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WERTYU
Time Limit : 2000/1000ms (Java/Other) Memory Limit : 131072/65536K (Java/Other)
Total Submission(s) : 6 Accepted Submission(s) : 3
Problem Description
A common typing error is to place the hands on the keyboard one row to the right of the correct position. So "Q" is typed as "W" and "J" is typed as "K" and so on. You are to decode a message typed in this manner.
Input
Input consists of several lines of text. Each line may contain digits, spaces, upper case letters (except Q, A, Z), or punctuation shown above [except back-quote (`)]. Keys labelled with words [Tab, BackSp, Control, etc.] are not represented in the input.
Output
You are to replace each letter or punctuation symbol by the one immediately to its left on the QWERTY keyboard shown above. Spaces in the input should be echoed in the output.
Sample Input
O S, GOMR YPFSU/
Sample Output
I AM FINE TODAY.
代码实现:
//WETYU
#include<stdio.h>
char s[]="`1234567890-=QWERTYUIOP[]ASDFGHJKL;'ZXCVBNM,./";
int main()
{
int i,c;
while((c=getchar())!=EOF)//逐个字符读入,每读入一个判断一个
{
for(i=1;s[i]&&s[i]!=c;i++) ;//在s数组中寻找存在的字符
if(s[i])//找到了就输出前一个字符
putchar(s[i-1]);//否则就只输出本身
else
putchar(c);
}
return 0;
}
#include<stdio.h>
char s[]="`1234567890-=QWERTYUIOP[]ASDFGHJKL;'ZXCVBNM,./";
int main()
{
int i,c;
while((c=getchar())!=EOF)//逐个字符读入,每读入一个判断一个
{
for(i=1;s[i]&&s[i]!=c;i++) ;//在s数组中寻找存在的字符
if(s[i])//找到了就输出前一个字符
putchar(s[i-1]);//否则就只输出本身
else
putchar(c);
}
return 0;
}
//实现思路特别好!值得学习
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