17 多校

Is Derek lying?

Time Limit: 3000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)
Total Submission(s): 22    Accepted Submission(s): 15

Problem Description

Derek and Alfia are good friends.Derek is Chinese,and Alfia is Austrian.This summer holiday,they both participate in the summer camp of Borussia Dortmund.During the summer camp,there will be fan tests at intervals.The test consists of N choice questions and each question is followed by three choices marked “A” “B” and “C”.Each question has only one correct answer and each question is worth 1 point.It means that if your answer for this question is right,you can get 1 point.The total score of a person is the sum of marks for all questions.When the test is over,the computer will tell Derek the total score of him and Alfia.Then Alfia will ask Derek the total score of her and he will tell her: “My total score is X,your total score is Y.”But Derek is naughty,sometimes he may lie to her. Here give you the answer that Derek and Alfia made,you should judge whether Derek is lying.If there exists a set of standard answer satisfy the total score that Derek said,you can consider he is not lying,otherwise he is lying.

 

Input

The first line consists of an integer T,represents the number of test cases.

For each test case,there will be three lines.

The first line consists of three integers N,X,Y,the meaning is mentioned above.

The second line consists of N characters,each character is “A” “B” or “C”,which represents the answer of Derek for each question.

The third line consists of N characters,the same form as the second line,which represents the answer of Alfia for each question.

Data Range:1≤N≤80000,0≤X,Y≤N,∑Ti=1N≤300000

 

Output

For each test case,the output will be only a line.

Please print “Lying” if you can make sure that Derek is lying,otherwise please print “Not lying”.

 

Sample Input

23 1 3AAAABC5 5 0ABCBCACBCB

 

Sample Output

Not lyingLying

 

题目链接：http://acm.hdu.edu.cn/showproblem.php?pid=6045

题意：给出两个人的选项和他们所得的分数，判断是否有人撒谎。

记两人答案相同的题目个数为A，答案不同的个数为B，题目总数为N，两人分别所得分数为X，Y，可以得到 X+Y > N + A 时一定有人撒谎了，因为答案不同的只能有其中一个人对，所以最大的分数和就是N+A。当一题中两人选项不同时有三种情况，一种是第一人对，还有是第二人对，或两人均错，所以两人的分差若大于B则其中有人说了假话，即abs( X+Y ) > B 时有人撒谎。

#include<iostream>#include<string.h>#include<stdio.h>using namespace std;int t,n,x,y,same;char s1[80100],s2[80100];int main(){    scanf("%d",&t);    while(t--)    {        scanf("%d%d%d",&n,&x,&y);        scanf("%s%s",s1,s2);        same = 0;        for(int i=0;i<n;i++)        {            if(s1[i]==s2[i])                same ++;        }        if(same+n>=x+y&&abs(x-y)<=n-same)            printf("Not lying\n");        else            printf("Lying\n");    }    return 0;}