Is Derek lying?

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Is Derek lying?
 



DerekDerek and AlfiaAlfia are good friends.DerekDerek is Chinese,and AlfiaAlfia is Austrian.This summer holiday,they both participate in the summer camp of Borussia Dortmund.During the summer camp,there will be fan tests at intervals.The test consists of NN choice questions and each question is followed by three choices marked “AA” “BB” and “CC”.Each question has only one correct answer and each question is worth 11 point.It means that if your answer for this question is right,you can get 11 point.The total score of a person is the sum of marks for all questions.When the test is over,the computer will tell DerekDerek the total score of him and AlfiaAlfia.Then AlfiaAlfia will ask DerekDerek the total score of her and he will tell her: “My total score is XX,your total score is YY.”But DerekDerek is naughty,sometimes he may lie to her. Here give you the answer that DerekDerek and AlfiaAlfia made,you should judge whether DerekDerek is lying.If there exists a set of standard answer satisfy the total score that DerekDerek said,you can consider he is not lying,otherwise he is lying.  
Input
The first line consists of an integer TT,represents the number of test cases. For each test case,there will be three lines. The first line consists of three integers NN,XX,YY,the meaning is mentioned above. The second line consists of NN characters,each character is “AA” “BB” or “CC”,which represents the answer of DerekDerek for each question. The third line consists of NN characters,the same form as the second line,which represents the answer of AlfiaAlfia for each question. Data Range:1N800001≤N≤80000,0X,YN,0≤X,Y≤N,Ti=1N300000∑i=1TN≤300000
Output
For each test case,the output will be only a line. Please print “LyingLying” if you can make sure that DerekDerek is lying,otherwise please print “Not lyingNot lying”.
Sample Input
23 1 3AAAABC5 5 0ABCBCACBCB
Sample Output
Not lyingLying
这个题真心坑到我们队了,改了n多次,直接心态爆炸,前2小时一个题没做,第三个小时连A,
确实无语,交了十几次。最后还是一脸懵的A了这题。
说一下正确的思路:
总得分一定不大于n+ans,得分差一定不大于n-ans。
注意前面的一个条件n+ans
#include<bits/stdc++.h>using namespace std;char a[300010],b[300010];int main(){    int T;    cin>>T;    int n,da,db;    while(T--)    {        int ans=0;        scanf("%d%d%d",&n,&db,&da);        scanf("%s",a);        scanf("%s",b);        for(int i=0;i<n;i++)           if(a[i]==b[i])               ans++;        if(da+db-2*ans<=(n-ans)&&(abs(da-db)<=n-ans))puts("Not lying");         else               puts("Lying");    }    return 0;}

  

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