生产消费中的死锁问题

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一个生产者，两个消费者，MAX=1，

有一个时刻，所有的线程都进入等待队列。

解决死锁问题，见以下代码：

package java.thread;/** * 生产消费中的死锁问题 */public class ThreadDemo6 {public static void main(String[] args) {//使用java中集合类，List是列表。Pool1 pool = new Pool1();Productor p1 = new Productor("生产者1", pool);p1.setName("p1");Consumer1 c1 = new Consumer1("消费者", pool);c1.setName("c1");Consumer1 c2 = new Consumer1("消费者", pool);c2.setName("c2");p1.start();c1.start();c2.start();}}//生产者class Productor extends Thread {static int i = 0;private String name;private Pool1 pool;public Productor(String name, Pool1 pool) {this.name = name;this.pool = pool;}public void run() {while (true) {pool.add(i++);}}}//消费者class Consumer1 extends Thread {private String name;private Pool1 pool;public Consumer1(String name, Pool1 pool) {this.name = name;this.pool = pool;}public void run() {while (true) {pool.remove();//System.out.println("-: " + i);}}}/** * 池子 */class Pool1 {private java.util.List<Integer> list = new java.util.ArrayList<Integer>();//容器最大值private int MAX = 1;//添加元素public void add(int n) {synchronized (this) {try {String name = Thread.currentThread().getName();while (list.size() == MAX) {System.out.println(name + ".wait()");//限时等待。this.wait();}list.add(n);System.out.println(name + " + : " + n);System.out.println(name + ".notify()");this.notifyAll();} catch (Exception e) {e.printStackTrace();}}}//删除元素public int remove() {synchronized (this) {try {String name = Thread.currentThread().getName();while (list.size() == 0) {System.out.println(name + ".wait()");this.wait();}int i = list.remove(0);System.out.println(name + " - : " + i);System.out.println(name + ".notify()");this.notifyAll();return i;} catch (Exception e) {e.printStackTrace();}return -1;}}}

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