状态机实例之密码锁（C语言实现）

密码2479

 

#include <stdio.h>

#include <stdlib.h>

#include <string.h>

typedef enum{

STATE0 = 0,

STATE1,

STATE2,

STATE3,

STATE4,//password pass

//...ADD here

}STATE;

typedef enum{

INPUT1 = '2',

INPUT2 = '4',

INPUT3 = '7',

INPUT4 = '9',

}INPUT;

int main()

{

char ch;

STATE current_state = STATE0;

while(1){

printf("请输入数字进行解码:");

while((ch = getchar()) != '/n'){

if((ch < '0') || (ch > '9')){

printf("非数字，请重新输入!/n");

break;

}

switch(current_state){

case STATE0:

if(ch == '2') current_state = STATE1;

break;

case STATE1:

if(ch == '4') current_state = STATE2;

break;

case STATE2:

if(ch == '7') current_state = STATE3;

break;

case STATE3:

if(ch == '9') current_state = STATE4;

break;

default:

current_state = STATE0;

break;

}

}

if(current_state == STATE4){

printf("Correct, lock is open!/n");

break;

}else

printf("Wrong, unlocked!/n");

}

return 0;

}