1025. PAT Ranking (25)
来源:互联网 发布:算法的乐趣 epub 编辑:程序博客网 时间:2024/06/04 20:05
1025. PAT Ranking (25)
Programming Ability Test (PAT) is organized by the College of Computer Science and Technology of Zhejiang University. Each test is supposed to run simultaneously in several places, and the ranklists will be merged immediately after the test. Now it is your job to write a program to correctly merge all the ranklists and generate the final rank.
Input Specification:
Each input file contains one test case. For each case, the first line contains a positive number N (<=100), the number of test locations. Then N ranklists follow, each starts with a line containing a positive integer K (<=300), the number of testees, and then K lines containing the registration number (a 13-digit number) and the total score of each testee. All the numbers in a line are separated by a space.
Output Specification:
For each test case, first print in one line the total number of testees. Then print the final ranklist in the following format:
registration_number final_rank location_number local_rank
The locations are numbered from 1 to N. The output must be sorted in nondecreasing order of the final ranks. The testees with the same score must have the same rank, and the output must be sorted in nondecreasing order of their registration numbers.
Sample Input:251234567890001 951234567890005 1001234567890003 951234567890002 771234567890004 8541234567890013 651234567890011 251234567890014 1001234567890012 85Sample Output:
91234567890005 1 1 11234567890014 1 2 11234567890001 3 1 21234567890003 3 1 21234567890004 5 1 41234567890012 5 2 21234567890002 7 1 51234567890013 8 2 31234567890011 9 2 4
提交代码
#include<stdio.h>#include<string.h>#include<algorithm>using namespace std;//创建一个结构体方便编写代码 struct Student{char id[15];//准考证号 int score;//分数 int local_num;//考场号 int local_rank;//考场内排名 }stu[30010]; //建立排序规则,详情请了解sort函数的用法 bool cmp(Student a,Student b){if(a.score!=b.score){return a.score>b.score;//先按分数从高到低排列 }else{return strcmp(a.id,b.id)<0;//分数相同按准考证号从小到大排序 }}int main(){int num=0,k,n;//num为学生总数,n为考场数 scanf("%d",&n);//读入有几个考场 for(int i=1;i<=n;i++){scanf("%d",&k);//读入该考场考生人数 for(int j=0;j<k;j++)//读入该考场考生的信息 {scanf("%s %d",stu[num].id,&stu[num].score);stu[num].local_num=i;num++;}sort(stu+num-k,stu+num,cmp);//给该考场的考生排序 stu[num-k].local_rank=1;for(int j=num-k+1;j<num;j++)//给该考场考生定排名 {if(stu[j].score==stu[j-1].score){stu[j].local_rank=stu[j-1].local_rank;}else{stu[j].local_rank=j+1-(num-k);}}}printf("%d\n",num); sort(stu,stu+num,cmp);int r=1;for(int i=0;i<num;i++)//给全部考生定排名 {if(i>0&&(stu[i].score!=stu[i-1].score)){r=i+1;}printf("%s %d %d %d\n",stu[i].id,r,stu[i].local_num,stu[i].local_rank);}return 0;}
- 1025. PAT Ranking (25)
- 1025. PAT Ranking (25)
- 1025. PAT Ranking (25)
- 1025. PAT Ranking (25)
- 1025. PAT Ranking (25)
- 1025. PAT Ranking (25)
- 1025. PAT Ranking (25)
- 1025. PAT Ranking (25)
- 1025. PAT Ranking (25)
- 1025. PAT Ranking (25)
- 1025. PAT Ranking (25)
- 1025. PAT Ranking (25)
- 1025. PAT Ranking (25)
- 1025. PAT Ranking (25)
- 1025. PAT Ranking (25)
- 1025. PAT Ranking (25)
- 1025. PAT Ranking (25)
- 1025. PAT Ranking (25)
- 橙色预警:Oracle游标泄露(open_cursor耗尽)
- Linux中Cron任务间隔执行:每隔几分钟/几小时/几天
- WEB应用的Session冲突
- java学习笔记:进制
- C++基础之字符串与指针
- 1025. PAT Ranking (25)
- 【二分+RMQ】玲珑oj 1149
- SVN常用命令
- 筛法快速求解素数
- 用matlab在图像上画矩形框,并保存坐标到文本中
- Codeforces Round 833A-The Meaningless Game
- ios-饼图和柱状图的绘制
- 多线程之初理解
- Linux和Windonws下静态库与动态库(动态库篇)