LeetCode

Given a non-negative integer num, repeatedly add all its digits until the result has only one digit.

For example:

Given num = 38, the process is like: 3 + 8 = 11, 1 + 1 = 2. Since 2 has only one digit, return it.

Follow up:
Could you do it without any loop/recursion in O(1) runtime?

嗯，找规律吧0 0

发现数字从小到大，答案1~9循环

class Solution {public:    int addDigits(int num) {        return 1 + (num - 1) % 9;    }};