智能版石头剪刀布——c++实现

利用c++实现了相对智能一点的石头剪刀布，方法是为计算机设置偏好，有第一偏好、第二偏好，第三偏好。同时计算机选择的时候会以百分之50的概率选择第一偏好，以百分之40的概率选择第二偏好，百分之10的概率选择第三偏好。

为了更加狡猾，设置全局变量记录运行局数，每隔三局（可以自行设定）分析用户的偏好，从而改变自身的偏好，可以使得计算机更为人性化，完成简单的人机交互。

这也是c++老师曾教给我们的，在Python的学习中遇到类似问题，拿出来温习一下，后续会编写出Python版的。

#include<iostream>#include<string>#include<ctime>#include<cstdlib>#define interval 3//间隔为3局 //#define 1 rock //#define 2 paper//#define 3 scissorsusing namespace std;//enum class choice(rock,paper,scissors); //using namespace choice;//choice player_choice;//choice computer_choice;string words[3]={"rock","paper","scissors"};int player_choice;int computer_choice;int player_wins=0;int computer_wins=0;int game_numbers=0;//游戏局数int x=0,y=0,z=0;//石头，布，剪刀的次数 int favorite;  //第一偏好 int second_favorite; //第二偏好 int third_favorite; //第三偏好 //choice get_computer_choice();int get_computer_choice();void decide_winner();string get_msg(int winner);int randOtoN1(int n);int max_number(int x,int y,int z);int main(){srand(time(NULL));string input_str;char c;while(true){cout<<"enter rock,paper,scissors or exit"<<endl;getline(cin,input_str);if(input_str.size()<1){cout<<"invalid input."<<endl;continue;//结束本次循环 }game_numbers++;//局数加一 c=input_str[0];//取首字母 if(c=='R'||c=='r'){//出石头 x++;player_choice=0;//0表示石头 }else if(c=='p'||c=='P'){y++;player_choice=1;//1表示布 }else if(c=='S'||c=='s'){z++;player_choice=2;//2表示剪刀 }else if(c=='E'||c=='e')//退出 break;else{cout<<"invalid input."<<endl;continue;}computer_choice=get_computer_choice();//int p=(int) player_choice;int p=player_choice;//int c=(int) computer_choice;int c=computer_choice;//cout<<"you chose "<<words[p];cout<<"you chose "<<words[p];cout<<","<<endl;//cout<<"I chose"<<words[c];cout<<"I chose "<<words[c];cout<<","<<endl;decide_winner();cout<<"game numbers are:"<<game_numbers<<endl<<endl;}system("pause");return 0;}void set_favorite(){//设置计算机偏好 //随机选出第一第二第三偏好 ，以50%的概率选择第一偏好，40%概率选择第二偏好 int n = randOtoN1(3);favorite = n;int m = randOtoN1(2);if(m == 0){second_favorite = (n+1)%3;third_favorite = (n+2)%3;}else{second_favorite = (n+2)%3;third_favorite = (n+1)%3;}int max = max_number(x,y,z);        if((game_numbers)%interval == 0 && max != 0)//当局数等于间隔的整数倍时 且xyz不相等           //每隔三局判定用户偏好，制定策略           {           if(max == x)  {              favorite = 2;              if(y >= z){                  second_favorite = 3;                  third_favorite = 1;              }              else{                  second_favorite = 1;                  third_favorite = 3;              }           }           else if(max == y) {              favorite = 3;              if(x >= z){                  second_favorite = 2;                  third_favorite = 1;              }else{                  second_favorite = 1;                  third_favorite = 2;              }           }             else {               favorite = 1;               if(x >= y){                  second_favorite = 2;                  third_favorite = 3;               }else{                  second_favorite = 3;                  third_favorite = 2;               }           }         }  }int get_computer_choice(){set_favorite();int w = randOtoN1(10);if(w <= 5)  return favorite;else if (w > 5 && w < 8)  return second_favorite;else return third_favorite;}void decide_winner(){if(computer_choice==player_choice){cout<<"result is a tie"<<endl;cout<<"player wins:"<<player_wins<<endl;cout<<"computer wins:"<<computer_wins<<endl;return ;}//int p=static_cast<int>(play_choice);int p=player_choice;//int c=static_cast<int>(computer_choice);int c=computer_choice;if(p-c==1||p-c==-2){cout<<get_msg(player_choice);cout<<"you win"<<endl;player_wins++;}else{cout<<get_msg(computer_choice);cout<<"I win"<<endl;computer_wins++;}cout<<"player wins:"<<player_wins<<endl;cout<<"computer wins:"<<computer_wins<<endl;cout<<endl;}string get_msg(int winner){if(winner==0) return string("Rock smashes scissors...");else if(winner==1) return string("paper smashes rock...");else return string("scissors smashes paper...");} int randOtoN1(int n) //产生随机数的函数 {return rand()%n;}int max_number(int x,int y,int z){int max;if(x==y&&y==z)  return 0;if(x>=y&&x>=z)  max=x;else if(y>=x&&y>=z) max=y;else max=z;return max;}