225. Implement Stack using Queues(java)
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Implement the following operations of a stack using queues.
- push(x) -- Push element x onto stack.
- pop() -- Removes the element on top of the stack.
- top() -- Get the top element.
- empty() -- Return whether the stack is empty.
- You must use only standard operations of a queue -- which means only
push to back
,peek/pop from front
,size
, andis empty
operations are valid. - Depending on your language, queue may not be supported natively. You may simulate a queue by using a list or deque (double-ended queue), as long as you use only standard operations of a queue.
- You may assume that all operations are valid (for example, no pop or top operations will be called on an empty stack).
思路:用两个队列q1,q2实现一个栈。push时把新元素添加到q1的队尾。pop时把q1中除最后一个元素外逐个添加到q2中,然后pop掉q1中的最后一个元素,然后交换q1和q2,以保证添加元素时始终向q1中添加。
public class MyStack { private Queue<Integer> q1; private Queue<Integer> q2; /** Initialize your data structure here. */ public MyStack() { q1=new LinkedList<>(); q2=new LinkedList<>(); } /** Push element x onto stack. */ public void push(int x) { q1.offer(x); } /** Removes the element on top of the stack and returns that element. */ public int pop() { while(q1.size()>1){ q2.offer(q1.poll()); } int pop=q1.poll(); //while(q2.isEmpty()){ // q1.add(q2.remove());} Queue<Integer> tmp=q1; q1=q2; q2=tmp; return pop; } /** Get the top element. */ public int top() { while(q1.size()>1){ q2.offer(q1.poll()); } int top=q1.peek(); q2.offer(q1.poll()); Queue<Integer> tmp=q1; q1=q2; q2=tmp; return top; } /** Returns whether the stack is empty. */ public boolean empty() { return q1.isEmpty(); }}/** * Your MyStack object will be instantiated and called as such: * MyStack obj = new MyStack(); * obj.push(x); * int param_2 = obj.pop(); * int param_3 = obj.top(); * boolean param_4 = obj.empty(); */
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